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24x^2+7x=12
We move all terms to the left:
24x^2+7x-(12)=0
a = 24; b = 7; c = -12;
Δ = b2-4ac
Δ = 72-4·24·(-12)
Δ = 1201
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{1201}}{2*24}=\frac{-7-\sqrt{1201}}{48} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{1201}}{2*24}=\frac{-7+\sqrt{1201}}{48} $
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